$$ I_C+ I_R + I_L =0 $$
$$ Q_C= C V $$
$$ I_R R_L = V $$
$$ L \frac{d I_L}{dt} = V $$
$$ I_C+ I_R + I_L =0 $$
$$ I_C= C \frac{d V}{dt} $$
$$ I_R R_L = V $$
$$ L \frac{d I_L}{dt} = V $$
$$ \frac{d I_C}{dt}+ \frac{d I_R}{dt} + \frac{d I_L}{dt} =0 $$
$$ \frac{d I_C}{dt}= C \frac{d^2 V}{dt^2} $$
$$ \frac{d I_R}{dt} =\frac{1}{R_L} \frac{d V}{dt} $$
$$ \frac{d I_L}{dt} =\frac{1}{L} V $$
$$C \frac{d^2 V}{dt^2} + \frac{1}{R_L} \frac{d V}{dt} + \frac{1}{L} V = 0$$
$$V(t)= V_o \cos(\omega t +\phi) \exp(-\beta t)$$
$$ \beta=\frac{1}{2 R_L C} $$
$$ \omega =\sqrt{\frac{1}{L C}- \beta^2}$$
$$ \beta=\frac{1}{2 R_L C_1} $$
$$ \omega =\sqrt{\frac{1}{L_1 C_1}- \beta^2}$$
om de waarde van de spoel $L_1$ te kiezen.
$$ \omega =\sqrt{\frac{1}{L_1 C_1}}$$
$$ P_{AC} =\frac{V_{AC}^2}{2 R_L}$$
* Class C amp 1
Q_Q1 2 1 0 Q2
L_L1 2 3 1uH
C_C1 2 3 10nF
R_RL 2 3 60
V_Vdd 3 0 11V
R_Rin 4 1 100
V_Vin 4 0 sin(-1.5 2.7 1591500) DC=-1.5
.model Q2 NPN(Is=14.34f BF=200)
* Class C amp 1
Q_Q1 2 1 0 Q2
L_L1 2 3 1uH
C_C1 2 3 10n
R_RL 2 3 60
V_Vdd 3 0 11V
R_Rin 4 1 100
V_Vin 4 5 AC 0.5V 0 DC 0
V_VinDC 5 0 0.7V
.model Q2 NPN(Is=14.34f BF=200)
* klasseC versie2
Q_Q1 2 1 0 Q2
L_L1 0 3 1uH
C_C1 0 3 10n
R_R1 0 3 100
V_V3 4 0 11V
V_V5 1 0 sin(-2 3.09 1591500) DC=-2
C_C2 2 3 100n
L_L2 2 4 20uH
.model Q2 NPN(Is=14.34f BF=255.9 Rb=100 )